擅长:python、mysql、java
<p>我认为<code>itertools.product()</code>实际上,<em>就是您要找的:</p>
<pre><code>pos = [['det'], ['noun', 'adj'], ['noun'],
['vb'], ['det'], ['vb', 'noun', 'adj']]
for x in itertools.product(*pos):
print " ".join(x)
</code></pre>
<p>印刷品</p>
^{pr2}$