在.txt文件中找到最常用单词的Python程序必须打印word及其连接

Question

现在，我有一个函数来替换countChars函数

def countWords(lines):
  wordDict = {}
  for line in lines:
    wordList = lines.split()
    for word in wordList:
      if word in wordDict: wordDict[word] += 1
      else: wordDict[word] = 1
  return wordDict

但当我运行这个程序时，它会吐出这种讨厌的东西（这只是一个例子，大约有两页文字旁边有大量的数字）

before 1478
battle-field 1478
as 1478
any 1478
altogether 1478
all 1478
ago 1478
advanced. 1478
add 1478
above 1478

虽然很明显这意味着代码足够运行，但我没有得到我想要的。 它需要打印文件中每个单词的次数（gb.txt，这是葛底斯堡地址） 很明显文件中的每个单词都不在1478次。。

我对编程很陌生，所以我有点困惑。。

from __future__ import division

inputFileName = 'gb.txt'

def readfile(fname):
  f = open(fname, 'r')
  s = f.read()
  f.close()
 return s.lower()

def countChars(t):
  charDict = {}
  for char in t:
    if char in charDict: charDict[char] += 1
    else: charDict[char] = 1
  return charDict

def findMostCommon(charDict):
  mostFreq = ''
  mostFreqCount = 0
  for k in charDict:
    if charDict[k] > mostFreqCount:
      mostFreqCount = charDict[k]
      mostFreq = k
  return mostFreq

def printCounts(charDict):
  for k in charDict:
    #First, handle some chars that don't show up very well when they print
    if k == '\n': print '\\n', charDict[k]  #newline
    elif k == ' ': print 'space', charDict[k]
    elif k == '\t': print '\\t', charDict[k] #tab
    else: print k, charDict[k]  #Normal character - print it with its count

def printAlphabetically(charDict):
  keyList = charDict.keys()
  keyList.sort()
  for k in keyList:
    #First, handle some chars that don't show up very well when they print
    if k == '\n': print '\\n', charDict[k]  #newline
    elif k == ' ': print 'space', charDict[k]
    elif k == '\t': print '\\t', charDict[k] #tab
    else: print k, charDict[k]  #Normal character - print it with its count

def printByFreq(charDict):
  aList = []
  for k in charDict:
    aList.append([charDict[k], k])
  aList.sort()     #Sort into ascending order
  aList.reverse()  #Put in descending order
  for item in aList:
    #First, handle some chars that don't show up very well when they print
    if item[1] == '\n': print '\\n', item[0]  #newline
    elif item[1] == ' ': print 'space', item[0]
    elif item[1] == '\t': print '\\t', item[0] #tab
    else: print item[1], item[0]  #Normal character - print it with its count

def main():
  text = readfile(inputFileName)
  charCounts = countChars(text)
  mostCommon = findMostCommon(charCounts)
  #print mostCommon + ':', charCounts[mostCommon]
  #printCounts(charCounts)
  #printAlphabetically(charCounts)
  printByFreq(charCounts)

main()

Answer 1

你有一个简单的排版，words在你想要的地方word。

编辑：您似乎已经编辑了源。请使用“复制粘贴”功能，以便在第一次使用时正确完成。

编辑2:显然你不是唯一一个容易出错的人。真正的问题是你有lines你想要的line。很抱歉，我指责你编辑了源代码。