Django restframework singleton Vi

Question

我需要通过django rest_framework将一组配置设置（键值对）传递给api enpoint。只读也可以。django1.7、Python3和rest frameworkv3.0.5。在

我有pip installeddjango-solo，我可以在管理部分访问它，所以我假设它可以工作。我已经设置了一个有效的路由，现在我需要创建一个真正返回数据的“类似视图的东西”。在

就我所知（绝对是错的）：

class ConfigViewSet(mixins.ListModelMixin,
                    mixins.RetrieveModelMixin,
                    viewsets.GenericViewSet):

    model = SiteConfiguration
    permission_classes = (IsAuthenticatedOrReadOnly,)

    def get_serializer_class(self):
        # What goes here? I want _all_ the settings

    def get_object(self):
        obj = self.model.get_solo()
        self.check_object_permissions(self.request, obj)
        return obj

    def list(self, *args, **kwargs):
        return self.retrieve(*args, **kwargs) 

任何帮助和提示，谢谢。在

PS！这是具有以下设置的config/models.py：

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Answer 1

Oki，这里是：

1）pip安装“django solo”。在

2）用manage.py startapp config制作一个新的应用程序。在

2a）文件config/models.py：

from django.db import models
from solo.models import SingletonModel

class SiteConfiguration(SingletonModel):
    site_name = models.CharField(max_length=255, default='Site Name')
    maintenance_mode = models.BooleanField(default=False)

    def __str__(self):
        return u"Site Configuration"

    class Meta:
        verbose_name = "Site Configuration"

2b）文件config/views.py：

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3）下一个问题是将视图添加到路由器。使用DefaultRouter，不能注册APIview，所以这个人有一个简单的HybridRouter解决方案[https://stackoverflow.com/a/23321478/1008905]。在

3a）在您的项目文件夹（主urls.py-文件所在的位置）中创建一个custom_routers.py，内容如下：

from rest_framework import routers, views, reverse, response

class HybridRouter(routers.DefaultRouter):
    def __init__(self, *args, **kwargs):
        super(HybridRouter, self).__init__(*args, **kwargs)
        self._api_view_urls = {}

    def add_api_view(self, name, url):
        self._api_view_urls[name] = url

    def remove_api_view(self, name):
        del self._api_view_urls[name]

    @property
    def api_view_urls(self):
        ret = {}
        ret.update(self._api_view_urls)
        return ret

    def get_urls(self):
        urls = super(HybridRouter, self).get_urls()
        for api_view_key in self._api_view_urls.keys():
            urls.append(self._api_view_urls[api_view_key])
        return urls

    def get_api_root_view(self):
        # Copy the following block from Default Router
        api_root_dict = {}
        list_name = self.routes[0].name
        for prefix, viewset, basename in self.registry:
            api_root_dict[prefix] = list_name.format(basename=basename)
        api_view_urls = self._api_view_urls

        class APIRoot(views.APIView):
            _ignore_model_permissions = True

            def get(self, request, format=None):
                ret = {}
                for key, url_name in api_root_dict.items():
                    ret[key] = reverse.reverse(url_name, request=request, format=format)
                # In addition to what had been added, now add the APIView urls
                for api_view_key in api_view_urls.keys():
                    ret[api_view_key] = reverse.reverse(api_view_urls[api_view_key].name, request=request, format=format)
                return response.Response(ret)

        return APIRoot.as_view() 

3b）在主urls.py中执行以下操作：

from .custom_routers import HybridRouter

# The rest is from the `rest-framework` polls-tutorial.

rest_router = HybridRouter()
rest_router.register(r'users', UserViewSet)
rest_router.register(r'polls', PollViewSet)
rest_router.add_api_view("config", url(r'^config/$', configViews.SiteConfiguration.as_view(), name='site_configuration'))

# Wire up our API using automatic URL routing.
# Additionally, we include login URLs for the browsable API.
urlpatterns = [    
    url(r'^', include(rest_router.urls), name='rest_api'),    
    url(r'^auth/', include('rest_framework.urls', namespace='rest_framework')),
    url(r'^admin/', include(admin.site.urls), name='admin'), 
]

所有这些似乎对我有用。在