我试图在Python上制作一个html实体编码器/解码器,它的行为类似于PHP的htmlentities
和{
我的输入:
Lorem ÁÉÍÓÚÇÃOÁáéíóúção @#$%*()[]<>+ 0123456789
python decode.py
输出:
^{pr2}$现在,如果我将其作为自动键脚本运行,则会出现以下错误:
Script name: 'html_entity_decode'
Traceback (most recent call last):
File "/usr/local/lib/python2.7/dist-packages/autokey/service.py", line 454, in execute
exec script.code in scope
File "<string>", line 40, in <module>
File "/usr/local/lib/python2.7/dist-packages/autokey/scripting.py", line 42, in send_keys
self.mediator.send_string(keyString.decode("utf-8"))
File "/usr/lib/python2.7/encodings/utf_8.py", line 16, in decode
return codecs.utf_8_decode(input, errors, True)
UnicodeEncodeError: 'ascii' codec can't encode characters in position 6-12: ordinal not in range(128)
我做错什么了?脚本如下:
import htmlentitydefs
import re
entity_re = re.compile(r'&(%s|#(\d{1,5}|[xX]([\da-fA-F]{1,4})));' % '|'.join(
htmlentitydefs.name2codepoint.keys()))
def html_entity_decode(s, encoding='utf-8'):
if not isinstance(s, basestring):
raise TypeError('argument 1: expected string, %s found' \
% s.__class__.__name__)
def entity_2_unichr(matchobj):
g1, g2, g3 = matchobj.groups()
if g3 is not None:
codepoint = int(g3, 16)
elif g2 is not None:
codepoint = int(g2)
else:
codepoint = htmlentitydefs.name2codepoint[g1]
return unichr(codepoint)
if isinstance(s, unicode):
entity_2_chr = entity_2_unichr
else:
entity_2_chr = lambda o: entity_2_unichr(o).encode(encoding,
'xmlcharrefreplace')
def silent_entity_replace(matchobj):
try:
return entity_2_chr(matchobj)
except ValueError:
return matchobj.group(0)
return entity_re.sub(silent_entity_replace, s)
text = clipboard.get_selection()
text = html_entity_decode(text)
keyboard.send_keys("%s" % text)
我在一个要点上找到的,我不是作者。在
问题在于:
是unicode字符串。在
要解决此问题,请更换:
^{pr2}$签署人:
查看回溯跟踪,可能的问题是您正在将一个unicode字符串传递给键盘.发送键,它需要由testring编码的UTF-8。然后,autokey尝试解码字符串,但由于输入的是unicode而不是utf-8,所以失败了。这看起来像是autokey中的一个bug:除非字符串是真正的纯(byte)sstring,否则不应该尝试对字符串进行解码。在
如果这个猜测是正确的,那么您应该能够通过一个unicode实例来发送密钥来解决这个问题。试试这样的方法:
不需要assert,但它是一个方便的健全性检查,以确保html_entity_decode执行正确的操作。在
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