擅长:python、mysql、java
<p>问题是4之前的0。
如果您想存储这种信息,请尝试使用字符串。</p>
<pre><code>a = (2016,04,03) --> Error
a = (2016,4,3) --> No Error
a = ("2016","04","03") --> No Error
a = "2016-04-03" --> you could retrieve Year, Month and Day by splitting this string
</code></pre>
<p>在Python 2.x 04中被解释为八进制数。
在Python中,八进制数字是以0o4的形式写的,如这里所写的:<a href="http://docs.python.org/3.0/whatsnew/3.0.html#integers" rel="nofollow">http://docs.python.org/3.0/whatsnew/3.0.html#integers</a></p>