python Tkinter下拉菜单的问题

Question

下面的代码是一个将按钮附加到现有程序上的程序，这样可以在更友好的界面上而不是在代码内部进行选择。我试图使用下拉菜单，但是setEthAnt1函数似乎有一个错误：TypeError:setEthAnt1（）没有参数（给定1）。我不知道我没有交什么。有人有什么想法吗？在

from Tkinter import *
import ThreegroupsGraphics as three

def run():
    three.main()

def setEthAnt1():
    name = var.get()
    print name
    three.OneTo2Ant = name
    print three.OneTo2Ant

root = Tk()
var = StringVar()
var.set("Group 1 Ethnic Antagonism")
OptionMenu(root, var, "1","2","3","4","5","6","7","8","9","10", command = setEthAnt1).pack()
butn = Button(root, text = 'run',  command = run)
butn.pack()
root.mainloop() 

Answer 1

当您为OptionMenu指定命令时，所选项的值将被发送到该命令中，这实际上使变量获取（）不需要。见下文：

from Tkinter import *
import ThreegroupsGraphics as three

def run():
    three.main()

def setEthAnt1(name):
    print name
    three.OneTo2Ant = name
    print three.OneTo2Ant

root = Tk()
var = StringVar()
var.set("Group 1 Ethnic Antagonism")
OptionMenu(root, var, "1","2","3","4","5","6","7","8","9","10", command = setEthAnt1).pack()
butn = Button(root, text = 'run',  command = run)
butn.pack()
root.mainloop() 

如果您不希望setEthAnt1有任何参数并且仍然使用var.get()，那么可以为OptionMenu生成一个lamda函数的命令，如下所示：

^{pr2}$