Python Dict to CSV:应为缩进B

Question

尝试将输出写入csv，但出现缩进错误。我敢肯定这是个愚蠢的错误，但我不明白为什么会被扔掉。在

#!/usr/bin/env python

import csv
import copy
import os
import sys
import glob

#get current working dir, set count, and select file delimiter
os.chdir('/Users/Briana/Documents/Misc./PythonTest')

#parses through files and saves to a dict
series = {}
for fn in glob.glob('*.txt'):
    with open(fn) as f:
        series[fn] = (1 for line in f if line.strip() and not line.startswith('#')) 

print series

#save the dictionary with key/val pairs to a csv
with open('seriescount.csv', 'wb') as f: 
    w = csv.DictWriter(f, series.keys()) #error thrown here
    w.writeheader()
    w.writerow(sum(names.values()))

完全回溯：

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Answer 1

如果您在这里提交的代码与您的计算机上的代码完全相同，则似乎存在空格和制表符混合在一起。如果我复制你问题中出现的代码，它会以空格缩进；但是，如果我按“编辑”然后检查代码，前21行用空格缩进，第22-24行用制表符缩进。下面的代码修复了此错误；请注意按照此处显示的方式复制它：

#!/usr/bin/env python

import csv
import copy
import os
import sys
import glob

#get current working dir, set count, and select file delimiter
os.chdir('/Users/Briana/Documents/Misc./PythonTest')

#parses through files and saves to a dict
series = {}
for fn in glob.glob('*.txt'):
    with open(fn) as f:
        series[fn] = (1 for line in f if line.strip() and not line.startswith('#')) 

print series

#save the dictionary with key/val pairs to a csv
with open('seriescount.csv', 'wb') as f:
    w = csv.DictWriter(f, series.keys()) #error thrown here
    w.writeheader()
    w.writerow(sum(names.values()))

导致IndentationError: expected an indented block的常见原因有三种：

• 忽略或忘记缩进
• 缩进部分的注释块
• 缩进中混合制表符和空格