<p>我对OpenCV一无所知,所以我只能猜测问题所在。在</p>
<p>我猜你只是读了一次视频数据。如果它是一个视频流,那么你必须不断地读取和解释数据。在</p>
<pre><code>import sys
import cv2
from PyQt4 import QtGui
from PyQt4 import QtCore
from PyQt4.QtGui import QImage
import time
class VideoCapture(QtGui.QWidget):
update_video = QtCore.pyqtSignal()
def __init__(self, parent = None):
QtGui.QWidget().__init__()
self.camera = cv2.VideoCapture(0)
self.label = QtGui.QLabel()
layout = QtGui.QHBoxLayout()
self.setLayout(layout)
layout.addWidget(self.label)
# Create the worker Thread
self.workThread = WorkThread(self.readVideo)
self.update_video.connect(self.draw)
def start(self):
self.workerThread.start()
def stop(self):
self.workThread.alive = False
self.workThread.stop()
def readVideo(self):
"""Note this method is executed in a thread. No drawing can happen in a thread. Emit a signal to draw items."""
b, self.frame = self.camera.read()
self.update_video.emit() # Signals are slow this may happen too fast
def closeEvent(self, event):
self.stop()
return QtGui.QWidget.closeEvent(self, event)
#self.workThread.alive = False
#self.workThread.stop()
def draw(self):
print "I should Redraw"
height, width, channel = self.frame.shape
bpl = 3 * width
qImg = QImage(self.frame.data, width, height, bpl, QImage.Format_RGB888)
pix = QtGui.QPixmap(qImg)
self.label.setPixmap(pix)
# self.label.show() # The label is now a part of the widget layout
class WorkThread(QtCore.QThread):
def __init__(self, target=None, args=(), kwargs={}):
QtCore.QThread.__init__(self)
# I don't know how Qt's threads work, so I am treating it like a python thread
self.target = target
self.args = args
self.kwargs = kwargs
self.alive = True
def run(self):
while self.alive:
self.target(*self.args, **self.kwargs)
app = QtGui.QApplication(sys.argv)
test = VideoCapture()
test.start()
sys.exit(app.exec_())
</code></pre>
<p>因为你每秒只更新这么多次,所以你可以用定时器来代替线程。定时器可能更容易和更安全地使用。在</p>
^{pr2}$