Python子进程检查输出不工作

Question

我在试着做我的测试_脚本.py总的来说_脚本.py包含子流程。试验_脚本.py是一个小口和主程序_脚本.py应该用2个参数调用它，并捕获输出。代码如下：

测试_脚本.py

a = int(input())
b = int(input())

print(a+b)

main_脚本.py

^{pr2}$

这是我得到的错误：

Traceback (most recent call last):
  File "C:/Users/John/Desktop/main_script.py", line 2, in <module>
    subprocess.check_output(['python', 'test_script.py', 2,3])
  File "C:\Python34\lib\subprocess.py", line 607, in check_output
    with Popen(*popenargs, stdout=PIPE, **kwargs) as process:
  File "C:\Python34\lib\subprocess.py", line 858, in __init__
    restore_signals, start_new_session)
  File "C:\Python34\lib\subprocess.py", line 1085, in _execute_child
    args = list2cmdline(args)
  File "C:\Python34\lib\subprocess.py", line 663, in list2cmdline
    needquote = (" " in arg) or ("\t" in arg) or not arg
TypeError: argument of type 'int' is not iterable

Answer 1

{a1}

import subprocess                                                                      
subprocess.check_output("python test_script.py", stderr=subprocess.STDOUT, shell=True)

Answer 2

参数的所有部分都必须是字符串。请执行以下操作：

subprocess.check_output(['python', 'test_script.py', "2", "3"])

如果这个命令无法运行，您将得到一个异常。要捕获它并查看输出：

^{pr2}$

第二个脚本将失败，因为它需要来自stdin的输入，而主脚本正在发送2和{}作为参数。调查sys.argv