打开图像？Python

Question

我正在创建一个基于文本的labryinth游戏，但我想它需要一些图片来说明发生了什么。出于某种原因，当我试图转到a2（图片应该会弹出）时，它就死掉了。我是一个初学者，所以不要太评判我的代码

import Image
a1 = ("a1 Go to the start of the Labyrinth", "You're at the start of the labyrinth") #Start
a2 = ("a2 Go Left", "You've chosen to go left, unfortunatly it leads to nothing.") #Fail route
a3 = ("a3 Go Right", "You've chosen to go right.") #Right route
a4 = ("a4 Go Left", "You've chosen to go left") #Fail route
a5 = ("a5 Go Right", "You've chosen to go right") #Right route
a6 = ("a6 Go Right", "You've chosen to go right") #Fail route; end
a7 = ("a7 Go Left", "You've chosen to go left") #Fail route
a8 = ("a8 Go Left", "You've chosen to go left") #Fail route; end
a9 = ("a9 Go Right", "You've chosen to go right") #Fail route; end
a10 = ("a10 Go Forwards", "You've chosen to go forwards") #Right route
a11 = ("a11 Go left", "You've chosen to go left; Congratulations, you won! You may restart") #Right route; end; victory
fail = ("fail End game", "You lost!") #End game
b1 = ("b1 Go Left", "You've chosen to go left")
b2 = ("b2 Go Right", "You've chosen to go right")
b3 = ("b3 Go Left", "You've chosen to go left")

transitions = {
    a1: (a2, a3),
    a2: (fail, a1),
    a3: (b1,),
    b1: (a4, a5,),
    a4: (b2,),
    b2: (a7, a6,),
    a5: (b3,),
    b3: (a9, a10,),
    a6: (fail, a1),
    a7: (a8,),
    a8: (fail, a1),
    a9: (fail, a1),
    a10: (a11,),
    a11: (a1,)
}

location = a1

while True:
    print location[1]
    print ("Here you can: ")

    for (i, t) in enumerate(transitions[location]):
        print i + 1, t[0]

    choice = int(raw_input("Choose one "))
    location = transitions[location][choice - 1]

    if location == a2:
        Image.open(picture.jpg)
        Img.show

Answer 1

if location == a2:
    img = Image.open("picture.jpg")
    Img.show

确保图像的名称在parantesses中 这应该管用

Answer 2

打开任何文件

import os
os.startfile(<filepath>)

Answer 3

而不是

Image.open(picture.jpg)
Img.show

你应该有

from PIL import Image

#...

img = Image.open('picture.jpg')
img.show()

您可能还应该考虑使用另一个系统来显示您的消息，因为这样做需要大量的手动操作。研究字符串替换（使用%s或.format()）。