如何告诉Python将整数转换为单词

Question

我试图告诉Python将整数转换成单词。

示例：（使用墙上的99瓶啤酒）

我用这段代码编写了程序：

for i in range(99,0,-1):
    print i, "Bottles of beer on the wall,"
    print i, "bottles of beer."
    print "Take one down and pass it around,"
    print i-1, "bottles of beer on the wall."
    print

但我不知道如何编写程序，以便显示单词（即九十九、九十八等）而不是数字。

我在python的书中绞尽脑汁，我明白也许我还不明白for/if/elif/else循环，但我只是在旋转我的轮子。

有人能提供一些见解吗？我不是在寻找一个直接的答案，虽然这可能有助于我看到我的问题，只是任何东西都可以给我指出正确的方向将是伟大的。

Answer 1

屈折包可以做到这一点。

https://pypi.python.org/pypi/inflect

$ pip install inflect

然后：

>>>import inflect
>>>p = inflect.engine()
>>>p.number_to_words(99)
ninety-nine

Answer 2

使用可以在sourceforge找到的pynum2word模块

>>> import num2word
>>> num2word.to_card(15)
'fifteen'
>>> num2word.to_card(55)
'fifty-five'
>>> num2word.to_card(1555)
'one thousand, five hundred and fifty-five'

Answer 3

我们采用了一个现有的很好的解决方案(ref)将数字转换为单词，如下所示：

def numToWords(num,join=True):
    '''words = {} convert an integer number into words'''
    units = ['','one','two','three','four','five','six','seven','eight','nine']
    teens = ['','eleven','twelve','thirteen','fourteen','fifteen','sixteen', \
             'seventeen','eighteen','nineteen']
    tens = ['','ten','twenty','thirty','forty','fifty','sixty','seventy', \
            'eighty','ninety']
    thousands = ['','thousand','million','billion','trillion','quadrillion', \
                 'quintillion','sextillion','septillion','octillion', \
                 'nonillion','decillion','undecillion','duodecillion', \
                 'tredecillion','quattuordecillion','sexdecillion', \
                 'septendecillion','octodecillion','novemdecillion', \
                 'vigintillion']
    words = []
    if num==0: words.append('zero')
    else:
        numStr = '%d'%num
        numStrLen = len(numStr)
        groups = (numStrLen+2)/3
        numStr = numStr.zfill(groups*3)
        for i in range(0,groups*3,3):
            h,t,u = int(numStr[i]),int(numStr[i+1]),int(numStr[i+2])
            g = groups-(i/3+1)
            if h>=1:
                words.append(units[h])
                words.append('hundred')
            if t>1:
                words.append(tens[t])
                if u>=1: words.append(units[u])
            elif t==1:
                if u>=1: words.append(teens[u])
                else: words.append(tens[t])
            else:
                if u>=1: words.append(units[u])
            if (g>=1) and ((h+t+u)>0): words.append(thousands[g]+',')
    if join: return ' '.join(words)
    return words

#example usages:
print numToWords(0)
print numToWords(11)
print numToWords(110)
print numToWords(1001000025)
print numToWords(123456789012)

结果：

zero
eleven
one hundred ten
one billion, one million, twenty five
one hundred twenty three billion, four hundred fifty six million, seven hundred
eighty nine thousand, twelve

注意，它适用于整数。尽管如此，将一个浮点数分成两个整数部分并不重要。