人脸识别Python

Question

本文尝试用python进行主成分分析（PCA）进行人脸识别。在

现在我可以得到训练图像images和输入图像input_image之间的最小欧几里德距离。这是我的代码：

import os
from PIL import Image
import numpy as np
import glob
import numpy.linalg as linalg

#Step1: put database images into a 2D array
filenames = glob.glob('C:\\Users\\me\\Downloads\\/*.pgm')
filenames.sort()
img = [Image.open(fn).convert('L').resize((90, 90)) for fn in filenames]
images = np.asarray([np.array(im).flatten() for im in img])

#Step 2: find the mean image and the mean-shifted input images
mean_image = images.mean(axis=0)
shifted_images = images - mean_image

#Step 3: Covariance
c = np.asmatrix(shifted_images) * np.asmatrix(shifted_images.T)

#Step 4: Sorted eigenvalues and eigenvectors
eigenvalues,eigenvectors = linalg.eig(c)
idx = np.argsort(-eigenvalues)
eigenvalues = eigenvalues[idx]
eigenvectors = eigenvectors[:, idx]

#Step 5: Only keep the top 'num_eigenfaces' eigenvectors
num_components = 20
eigenvalues = eigenvalues[0:num_components].copy()
eigenvectors = eigenvectors[:, 0:num_components].copy()

#Step 6: Finding weights
w = eigenvectors.T * np.asmatrix(shifted_images) 
# check eigenvectors.T/eigenvectors 

#Step 7: Input image
input_image = Image.open('C:\\Users\\me\\Test\\5.pgm').convert('L').resize((90, 90))
input_image = np.asarray(input_image).flatten()

#Step 8: get the normalized image, covariance, 
# eigenvalues and eigenvectors for input image
shifted_in = input_image - mean_image
c = np.cov(input_image)
cmat = c.reshape(1,1)
eigenvalues_in, eigenvectors_in = linalg.eig(cmat)

#Step 9: Find weights of input image
w_in = eigenvectors_in.T * np.asmatrix(shifted_in) 
# check eigenvectors/eigenvectors_in

#Step 10: Euclidean distance
d = np.sqrt(np.sum(np.asarray(w - w_in)**2, axis=1))
idx = np.argmin(d)
print idx

我现在的问题是，我想返回最小欧几里德距离的图像（或它在数组images中的索引），而不是它在距离数组中的索引{}

Answer 1

我不认为您修改了图像在w中的存储顺序，因此，np.argmin(d)中的{}应该与{}列表的索引相同，所以

images[idx]

应该是你想要的形象。在

当然了

^{pr2}$

会给出(1800,)，因为它仍然是扁平的。如果您想解开它，可以执行以下操作：

^{3}$