mayavi映射su上的离散色条

2024-04-25 08:10:29 发布

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我想根据另一个取离散值的值(ID)来改变曲面的颜色(所以我需要一个离散的颜色条)。 在下面的简化示例中,我绘制了一个具有3个不同ID的球体:

0/左侧红色

2/中间蓝色

1/左边是绿色

但是通过下面的代码,我得到了一些奇怪的行为(绿点)在红色和蓝色之间的极限。 可能是因为插值!在

代码:

from mayavi import mlab
import numpy as np

# my dataset -simplified-
x,y,z = np.mgrid[-3:3:100j, -3:3:100j, -3:3:100j]
values = np.sqrt(x**2 + y**2 + z **2)

# my color values : the volume is divided in 3 sub-volumes along x taking 
colorvalues=np.empty(values.shape)
colorvalues[0:33,:,:]=0.
colorvalues[33:66,:,:]=2.
colorvalues[66:,:,:]  =1.

src = mlab.pipeline.scalar_field(values)
src.image_data.point_data.add_array(colorvalues.T.ravel())
src.image_data.point_data.get_array(1).name = 'myID'
src.image_data.point_data.update()

# the surface i am interested on
contour = mlab.pipeline.contour(src)
contour.filter.contours= [2.8,]

# to map the ID
contour2 = mlab.pipeline.set_active_attribute(contour, point_scalars='myID')

# And we display the surface The colormap is the current attribute: the ID.
mySurf=mlab.pipeline.surface(contour2)

# I change my colormap to a discrete one : R-G-B 
mySurf.module_manager.scalar_lut_manager.lut.table = np.array([[255,0,0,255],[0,255,0,255],[0,0,255,255]])

mlab.colorbar(title='ID', orientation='vertical', nb_labels=3)      
mlab.show()

Image

我以前也试过这条线mlab.表演():

^{pr2}$

渲染效果更好,但绿色点变成了绿色条纹。在

Image


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1条回答
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1楼 · 发布于 2024-04-25 08:10:29

我已经找到了我的答案,使用了一个凌乱的最近邻插值和使用一个颜色的细胞我的对象。在

from mayavi import mlab
import numpy as np
import scipy.interpolate

# my dataset -simplified-
x,y,z = np.mgrid[-3:3:100j, -3:3:100j, -3:3:100j]
values = np.sqrt(x**2 + y**2 + z **2)

# my color values : the volume is divided in 3 sub-volumes along x taking 
colorvalues=np.empty(values.shape)
colorvalues[0:33,:,:]=0.
colorvalues[33:66,:,:]=2.
colorvalues[66:,:,:]  =1.

src = mlab.pipeline.scalar_field(x,y,z ,values)

# the surface i am interested on
contour = mlab.pipeline.contour(src)
contour.filter.contours= [2.8,]

# I extract points that form my surface
PtsCoord = contour.outputs[0].points.to_array()

# then the variable that contains the indices of the points forming triangles.
PolyAndTriIDs = contour.outputs[0].polys.to_array() 
PolyAndTriIDs = PolyAndTriIDs.reshape(PolyAndTriIDs.size/4,4)

# Coordinates of each triangle
x1,y1,z1 = PtsCoord[PolyAndTriIDs[:,1]].T
x2,y2,z2 = PtsCoord[PolyAndTriIDs[:,2]].T
x3,y3,z3 = PtsCoord[PolyAndTriIDs[:,3]].T

# I interpolate the color value at the center of triangles with the Nearest-neighbour interpolation method
interp0 = scipy.interpolate.NearestNDInterpolator( (x.ravel(),y.ravel(),z.ravel()), colorvalues.ravel() )
result0 = interp0((np.mean((x1,x2,x3),0),np.mean((y1,y2,y3),0),np.mean((z1,z2,z3),0)))

# Displaying with triangular_mesh and color given by cell scalar value
mesh = mlab.triangular_mesh(PtsCoord[:,0], PtsCoord[:,1], PtsCoord[:,2], PolyAndTriIDs[:,1:])
cell_data = mesh.mlab_source.dataset.cell_data
cell_data.scalars = result0
cell_data.scalars.name = 'Cell data'
cell_data.update()
mesh.actor.mapper.scalar_mode = 'use_cell_data'
mesh.module_manager.scalar_lut_manager.lut.table = np.array([[255,0,0,255],[0,255,0,255],[0,0,255,255]])
mesh.module_manager.scalar_lut_manager.use_default_range = False 
mesh.module_manager.scalar_lut_manager.data_range = [ 0.,  2.]

mlab.colorbar(title='ID', orientation='vertical', nb_labels=3)

结果不那么平滑,但更具相关性。在

exmple OK

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