python object（）不接受参数

Question

我不敢相信这实际上是一个问题，但我一直在试图调试这个错误，我没有得到任何结果。我肯定我错过了一些很简单的东西，因为这看起来太傻了。

import Experiences, Places, Countries
class Experience(object):

    def make_place(self, place):
        addr = place["address"]
        addr = Places.ttypes.Address(addr["street"], addr["city"], addr["state"], Countries.ttypes._NAMES_TO_VALUES[addr["country"]], addr["zipcode"])
        ll = Geocoder.geocode(addr["street"]+", "+addr["city"]+", "+addr["state"]+" "+addr["zipcode"])
        place["location"] = Places.ttypes.Location(ll[0].coordinates[0], ll[0].coordinates[1])

    def __init__(self, exp_dict):
        exp_dict["datetimeInterval"] = Experiences.ttypes.DateTimeInterval(remove(exp_dict, "startTime"), remove(exp_dict, "endTime"))
        exp_dict["type"] = Experiences.ttypes.ExperienceType.OPEN
        exp_dict["place"] = self.make_place(exp_dict["place"])
        self.obj = Experiences.ttypes.Experience(**exp_dict)

@client.request
@client.catchClientException
def addExperience(thrift, access_token, exp_dict):
    experience = Experience(exp_dict)
    return thrift.client.addExperience(thrift.CLIENT_KEY, access_token, experience.obj)

（与addExperience对应的两个decorator是因为它是在声明其类的文件外部定义的。）

我得到的错误是：

experience = Experience(exp_dict)
TypeError: object() takes no parameters

所以这对我来说毫无意义，因为我清楚地向init函数声明了第二个参数。任何帮助都会很棒的！

Traceback (most recent call last):
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1477, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1381, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1475, in full_dispatch_request
    rv = self.dispatch_request()
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-    packages/flask/app.py", line 1461, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/session.py", line 22, in check_login
    return f()
  File "/Users/phil/Hangify/hy-frontend-server/hangify/handlers/create.py", line 31, in Handle
    res = exp.addExperience(hangify.thrift_interface, access_token, experience)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/__init__.py", line 22, in decorator
    obj = func(client, *args, **kwargs)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/__init__.py", line 30, in decorator
    return func(*args, **kwargs)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/exp.py", line 39, in addExperience
    experience = Experience(exp_dict)
TypeError: object() takes no parameters

这里是Experience.mro（）-它指出了类Experience的正确模块位置：

[<class 'hangify.client.exp.Experience'>, <type 'object'>]

这里是dir（Experience）：

 ['__class__', '__delattr__', '__dict__', '__doc__', '__format__',
 '__getattribute__', '__hash__', '__init__', '__module__', '__new__',
 '__reduce__', '__reduce_ex__', '__repr__', '__setattr__',
 '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'make_place']

Answer 1

我也有这个错误。顺便说一下，我输入的是\uu int\u，而不是\uu init\uu。

我认为，在许多错误类型的情况下，我使用的IDE（IntelliJ）会将颜色更改为函数定义的默认设置。但是，在我的例子中，作为另一种dunder/magic方法，颜色与IDE为显示的颜色（默认的预定义项定义颜色）保持一致，这花了我一些时间来发现丢失的i。

Answer 2

我为此挣扎了一会儿。愚蠢的规则。两个“一起”就是“一起”

Answer 3

你混合了标签和空格。__init__实际上是嵌套在另一个方法中定义的，因此类没有自己的__init__方法，而是继承object.__init__。在记事本中打开代码，而不是使用任何编辑器，您将看到您的代码，正如Python的选项卡处理规则所看到的那样。

这就是为什么你不应该混合标签和空格。坚持到底。建议使用空格。