Django - 合并两个模型序列化器为一个JSON响应

2024-03-28 08:57:03 发布

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我有两份型号表和名片。我尝试将这两者结合起来,生成一个单独的JSON响应

我的列表JSON响应

[
    {
        "id": 1,
        "name": "List of things to do"
    },
    {
        "id": 2,
        "name": "one more"
    }
] 

我的卡JSON响应

^{pr2}$

我的序列化程序.py文件

from rest_framework import serializers
from .models import List, Card

class CardSerializer(serializers.ModelSerializer):

    class Meta:
        model = Card
        fields = '__all__'

class ListSerializer(serializers.ModelSerializer):
    cards = CardSerializer(read_only=True, many=True)

    class Meta:
        model = List
        fields ='__all__'

我的api.py文件文件

from rest_framework.viewsets import ModelViewSet
from .models import List, Card
from .serializers import ListSerializer, CardSerializer

class ListViewSet(ModelViewSet):
    queryset = List.objects.all()
    serializer_class = ListSerializer

class CardViewSet(ModelViewSet):
    queryset = Card.objects.all()
    serializer_class = CardSerializer

我的模型.py在

from django.db import models

class  List(models.Model):
    name = models.CharField(max_length=50) 

    def __str__(self):
        return "List : {}".format(self.name)

class Card(models.Model): # to create card table
    title = models.CharField(max_length=100)
    description = models.TextField(blank=True) 
    list = models.ForeignKey(List, related_name = "card" 
    ,on_delete=models.PROTECT) # creating a foriegn key for storing list
    story_points = models.IntegerField(null=True, blank = True)
    business_value = models.IntegerField(null=True, blank = True)
    def __str__(self):
        return "Card : {}".format(self.title)

如何在我的列表JSON响应中实现类似于下面的内容?在

[
    {
        "id": 1,
        "cards":[
        {
            "id": 1,
            "title": "My first scrum card",
            "description": "list things todo here",
            "story_points": null,
            "business_value": null,
            "list": 1
        }],
        "name": "List of things to do"
    },
    {
        "id": 2,
        "cards":[
        {
            "id": 2,
            "title": "File my taxes",
            "description": "fill it before 1st of nov",
            "story_points": null,
            "business_value": null,
            "list": 1
        }],
        "name": "one more"
    },
]

我已经试过了,但没能实现。所以我把它贴在这里了

标题

非常感谢。在


Tags: namefromimportidjsontruemodelsall
2条回答

将列表related_name更改为cardsListViewSet将执行您想要的操作

class Card(models.Model): # to create card table
    title = models.CharField(max_length=100)
    description = models.TextField(blank=True) 
    list = models.ForeignKey(List, related_name = "cards"
    ,on_delete=models.PROTECT)
...

{defirmeld也可以使用。在

class ListSerializer(serializers.ModelSerializer):
    cards = serializers.SerializerMethodField()

    class Meta:
       model = List
       fields = '__all__'

   def get_cards(self, obj):
       data = CardSerializer(obj.card.all(), many=True).data
       return data

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