Python中的简单URL GET/POST函数

2024-03-28 19:44:26 发布

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请求

https://github.com/kennethreitz/requests/

以下是一些常用的使用方法:

import requests
url = 'https://...'
payload = {'key1': 'value1', 'key2': 'value2'}

# GET
r = requests.get(url)

# GET with params in URL
r = requests.get(url, params=payload)

# POST with form-encoded data
r = requests.post(url, data=payload)

# POST with JSON 
import json
r = requests.post(url, data=json.dumps(payload))

# Response, status etc
r.text
r.status_code

httplib2

https://github.com/jcgregorio/httplib2

>>> from httplib2 import Http
>>> from urllib import urlencode
>>> h = Http()
>>> data = dict(name="Joe", comment="A test comment")
>>> resp, content = h.request("http://bitworking.org/news/223/Meet-Ares", "POST", urlencode(data))
>>> resp
{'status': '200', 'transfer-encoding': 'chunked', 'vary': 'Accept-Encoding,User-Agent',
 'server': 'Apache', 'connection': 'close', 'date': 'Tue, 31 Jul 2007 15:29:52 GMT', 
 'content-type': 'text/html'}

你可以用这个来包装urllib2:

def URLRequest(url, params, method="GET"):
    if method == "POST":
        return urllib2.Request(url, data=urllib.urlencode(params))
    else:
        return urllib2.Request(url + "?" + urllib.urlencode(params))

它将返回具有结果数据和响应代码的Request对象。

更简单:通过requests模块。

import requests
get_response = requests.get(url='http://google.com')
post_data = {'username':'joeb', 'password':'foobar'}
# POST some form-encoded data:
post_response = requests.post(url='http://httpbin.org/post', data=post_data)

若要发送非形式编码的数据,请将其序列化为字符串(示例取自documentation):

import json
post_response = requests.post(url='http://httpbin.org/post', data=json.dumps(post_data))
# If using requests v2.4.2 or later, pass the dict via the json parameter and it will be encoded directly:
post_response = requests.post(url='http://httpbin.org/post', json=post_data)

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