如何让乌龟连续移动而不需要多次按键？

Question

我在做一个游戏，玩家可以在屏幕底部的一条线上移动。在

此时要移动它，用户反复点击箭头键，但我想让它在按下键时连续移动。在

我怎么解决这个问题？在

Answer 1

您需要使用键的get_pressed（）功能，Link。在

import pygame
pygame.init()
# Variables
black_background = (0, 0, 0)
screen = pygame.display.set_mode((1280, 960))
running = True
turtle_image = pygame.image.load('location/to/turtle/image.png')
turtle_rect = turtle_image.get_rect() # Using rect allows for collisions to be checked later
# Set spawn position
turtle_rect.x = 60
turtle_rect.y = 60

while running:
    keys = pygame.key.get_pressed()  #keys pressed
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False

    if keys[pygame.K_LEFT]:
        turtle_rect.x -= 1
    if keys[pygame.K_RIGHT]:
        turtle_rect.x += 1

    screen.fill(black_background)
    screen.blit(turtle_image, turtle_rect)

请记住，这只是一个基本的布局，您需要进一步了解如何使用其他关键点来完成碰撞和/或移动。Intro Here.

Answer 2

下面是我基于海龟的解决方案。它使用一个计时器使海龟在窗口底部移动，但在没有任何事情发生时让计时器过期（turtle已在边缘停止），并根据需要重新启动计时器：

from turtle import Turtle, Screen

CURSOR_SIZE = 20

def move(new_direction=False):
    global direction

    momentum = direction is not None  # we're moving automatically

    if new_direction:
        direction = new_direction

    if direction == 'right' and turtle.xcor() < width / 2 - CURSOR_SIZE:
        turtle.forward(1)
    elif direction == 'left' and turtle.xcor() > CURSOR_SIZE - width / 2:
        turtle.backward(1)
    else:
        direction = None

    if ((not new_direction) and direction) or (new_direction and not momentum):
        screen.ontimer(move, 10)

screen = Screen()
width, height = screen.window_width(), screen.window_height()

turtle = Turtle('turtle', visible=False)
turtle.speed('fastest')
turtle.penup()
turtle.sety(CURSOR_SIZE - height / 2)
turtle.tilt(90)
turtle.showturtle()

direction = None

screen.onkeypress(lambda: move('left'), "Left")
screen.onkeypress(lambda: move('right'), "Right")

screen.listen()
screen.mainloop()

使用左右箭头控制海龟的方向。在