def cat_n_times(s, n):
while s != 0:
print(n)
s = s - 1
text = input("What would you like the computer to repeat back to you: ")
num = input("How many times: ")
cat_n_times(num, text)
def cat_n_times(s, n):
for i in range(n):
print(s)
text = input("What would you like the computer to repeat back to you: ")
num = int(input("How many times: ")) # Convert to an int immediately.
cat_n_times(text, num)
失败的原因是(Python 3)
input
返回一个字符串。要将其转换为整数,请使用int(some_string)
。在Python中,通常不会手动跟踪索引。实现这种功能的更好方法是
我把你的API改了一点。在我看来,
n
应该是的次数,而s
应该是的字符串。作为将来的参考,Python是strongly typed。与其他动态语言不同,它不会自动从一种类型或另一种类型(例如从
str
到int
)转换对象,因此您必须自己执行此操作。从长远来看你会喜欢的,相信我!相关问题 更多 >
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