如何有选择地转义Python字符串中的百分比（%）？

Question

我有以下代码

test = "have it break."
selectiveEscape = "Print percent % in sentence and not %s" % test

print(selectiveEscape)

我想得到输出：

Print percent % in sentence and not have it break.

实际发生的情况：

    selectiveEscape = "Use percent % in sentence and not %s" % test
TypeError: %d format: a number is required, not str

Answer 1

或者，从Python 2.6开始，您可以使用新的字符串格式（如PEP 3101所述）：

'Print percent % in sentence and not {0}'.format(test)

这是特别方便，因为你的字符串变得更复杂。

Answer 2

尝试使用%%打印%符号。

Answer 3

>>> test = "have it break."
>>> selectiveEscape = "Print percent %% in sentence and not %s" % test
>>> print selectiveEscape
Print percent % in sentence and not have it break.