使用python搜索并替换文件中的windows路径

Question

我在一个文件中有以下文本：

C:\Program Files\MyApp\

我想解析我的文件并将文本替换为：

D:\NewDest\

我使用下面的代码，但是我不能替换文本因为反斜杠-任何没有反斜杠的文本都可以。我该怎么办？在

import os, fnmatch
import fileinput, glob, string, sys, os
from os.path import join
import os
import re
import sys
def searchreplace(path,search,replace,exts=None):

    import fileinput, glob, string, sys, os
    from os.path import join
    # replace a string in multiple files
    #filesearch.py

    files = glob.glob(path + "/*")
    if files is not []:
        for file in files:
            if os.path.isfile(file):
                if exts is None or exts.count(os.path.splitext(file)[1]) is not 0:
                    print file
                    for line in fileinput.input(file):
                        line = re.sub(search,replace, line.rstrip())
                        print(line)

searchreplace('D:\Test', 'C:\Program Files\MyApp\', 'D:\NewDest\', '*.csproj')

Answer 1

一个反斜杠考虑转义序列。在

>>> a ="\"
  File "<stdin>", line 1
    a ="\"
         ^
SyntaxError: EOL while scanning string literal
>>> a ="\\"

您可以使用双斜杠。Windows允许使用双斜杠（“C:\Program Files\MyApp\”，“D:\NewDest\”）。在

Answer 2

您需要将路径中的\替换为\\。
以及正则表达式中每个\的\\\\。在

import os, fnmatch
import fileinput, glob, string, sys, os
from os.path import join
import os
import re
import sys
def searchreplace(path,search,replace,exts=None):

    import fileinput, glob, string, sys, os
    from os.path import join
    # replace a string in multiple files
    #filesearch.py

    files = glob.glob(path + "/*")
    if files is not []:
    for file in files:
        if os.path.isfile(file):
        if exts is None or exts.count(os.path.splitext(file)[1]) is not 0:
            print file
            for line in fileinput.input(file):
            line = re.sub(search,replace, line.rstrip())
            print(line)

searchreplace('D:\\Test', 'C:\\\\Program Files\\\\MyApp\\\\', 'D:\\\\NewDest\\\\', '*.txt')

参考号：Can't escape the backslash with regex?

Answer 3

尝试使用'D:\\Test'或r'D:\Test'代替'D:\Test'将反斜杠设为文字。所有字符串都一样。在