错误：“int”对象不可订阅-Python

Question

我试着用一段简单的代码，知道某人的名字和年龄，让他/她知道他们什么时候满21岁。。。不考虑消极因素，只是随机的。

我一直收到这个'int' object is not subscriptable错误。

name1 = raw_input("What's your name? ")
age1 = raw_input ("how old are you? ")
x = 0
int([x[age1]])
twentyone = 21 - x
print "Hi, " + name1+ " you will be 21 in: " + twentyone + " years."

Answer 1

当你写x = 0时，x是一个int…所以你不能做x[age1]，因为x是int

Answer 2

问题出在队伍里

int([x[age1]])

你想要的是

x = int(age1)

您还需要将int转换为输出的字符串。。。

print "Hi, " + name1+ " you will be 21 in: " + str(twentyone) + " years."

整个剧本看起来像

name1 = raw_input("What's your name? ")
age1 = raw_input ("how old are you? ")
x = 0
x = int(age1)
twentyone = 21 - x
print "Hi, " + name1+ " you will be 21 in: " + str(twentyone) + " years."

Answer 3

当您键入x = 0时，这将创建一个新的int变量（名称）并为其赋值零。

当您键入试图访问第age1条目的x[age1]时，就好像x是一个数组一样。