Django1.8模型表单字段在呈现temp时不显示

Question

我正在尝试创建一个窗体，允许用户将数据输入到我的数据库中。我遵循了许多教程，这可能会导致我的困惑。问题是我的页面显示了所有的html元素，但是表单没有显示。我不知道为什么。谁能帮忙吗？谢谢！在

这是我的代码：

    #forms for blocks  
    from django import forms
    from .models import Block
    class BlockForm(forms.ModelForm):

        class Meta:
            model = Block
            fields = ['block_status', 'block_name', 'block_derivatives',  'block_subsystems', 'owners']

    # def requests view.py
    def requests(request, inventory_id):
        inventory = get_object_or_404(Inventory, pk=inventory_id)
        #return render(request, 'inventory/requests.html', {'inventory':      inventory})
        form = BlockForm()
        if request.POST:
            form = BlockForm(request.POST)
            if form.is_valid():

                form.save()
                print"FUFUFUFUFUF"

                return HttpResponseRedirect('/inventory/2')
            else:

                form = BlockForm()
                print "LOLOLO"
            args = {}
            args.update(csrf(request))

            args['form'] = form

            return render_to_response('requests.html', args)
        print "HIHIHIHIHIH"
        return render(request, 'inventory/requests.html', {'inventory':  inventory})

    # urls
    from django.conf.urls import url
    from . import views

    urlpatterns = [
        url(r'^$', views.index, name='index'),
        url(r'^(?P<inventory_id>.*)/$', views.detail, name='detail'),
        url(r'^(?P<inventory_id>[0-9]+)/requests$', views.requests,   name='requests'),
        #url(r'^(?P<inventory_id>.*)block_form/$', views.block_form)
    ]

#requests.html

     <div class="blockform">
         <div class="container">
             <form action="{% url 'inventory:requests' inventory.id %}" method="post">{% csrf_token %}
                <ul>
                <li>Hello, world.</li>
                {{form.as_table}}
                </ul>
                <input type="submit" name="submit" value="Request Blocks">
            </form>
        </div>
    </div>

enter code here

Answer 1

如果请求是GET，则不会将表单传递给模板。在这种情况下，创建表单实例时，实际上不需要区分GET和POST。您可以简单地将表单实例化为：

form = BlockForm(request.POST or None)

并删除if request.POST之后的实例化。我也不知道你为什么要使用render_to_response如果这是一个POST vs render。在这两种情况下都可以使用render。在

你的观点只需要：

^{pr2}$