kateli1991

Python多处理密码



我在业余时间学习Python已经有一段时间了,我给自己设置了一个挑战,为一个非常具体的任务构建一个密码破解器,它是为了测试我的ADSL路由器的安全性(不是很有效)-使用Wireshark我可以很清楚地看到它是如何通过http散列密码的,我开发了一些代码执行单词表攻击。(如果你认为我的代码写得不好,我很抱歉-你可能是正确的!)。在

#!/usr/bin/env python

import hashlib, os, time, math
from hashlib import md5

def screen_clear():
    if os.name == 'nt':
        return os.system('cls')
    else:
        return os.system('clear')

screen_clear()

print ""
print "Welcome to the Technicolor md5 cracker"
print ""

user = raw_input("Username: ")
print ""
nonce = raw_input("Nonce: ")
print ""
hash = raw_input("Hash: ")
print ""
file = raw_input("Wordlist: ")
print ""

realm = "Technicolor Gateway"
qop = "auth"
uri = "/login.lp"

HA2 = md5("GET" + ":" + uri).hexdigest()

wordlist = open(file, 'r')

time1 = time.time()

for word in wordlist:
    pwd = word.replace("\n","") 
    HA1 = md5(user + ":" + realm + ":" + pwd).hexdigest()
    hidepw = md5(HA1 + ":" + nonce +":" + "00000001" + ":" + "xyz" + ":" + qop + ":" + HA2).hexdigest()
    if hidepw == hash:
        screen_clear()
        time2 = time.time()
        timetotal = math.ceil(time2 - time1)
        print pwd + " = " + hidepw + " (in " + str(timetotal) + " seconds)"
        print ""
        end = raw_input("hit enter to exit")
        exit()

wordlist.close()

screen_clear()
time2 = time.time()
totaltime = math.ceil(time2 - time1)
print "Sorry, out of " + str(tested) + " passwords tested, your password was not found (in " + str(totaltime) + " seconds)"
print ""
end = raw_input("hit enter to exit")
screen_clear()
exit()

这很好的工作,但我想要更多,所以我想我可以添加一些多处理能力,以加快事情-使用各种不同的指令和指南,我没有得到一个成功的结果!(虽然感觉我很亲近)

请有人告诉我“多核python密码破解的白痴指南”,或者帮助我修改我的代码。在

另外,我最初的计划是使用opencl或cuda…但我很快就知道我是多么的无能为力!在


已被浏览了317次
6 日,19 小时 之前提问
1 个回答
fefe Tyson

我已经为您做了一个例子,应该相对容易添加到您的代码中。它的工作原理如下:首先,我们需要将wordlist压缩成可管理的块,然后将其放入多处理器模块。我用字典列一个表,上面有“开始”和“停止”点。接下来,我将这些参数传递到apply_async中,它将依次运行pwd_find函数。这是您想要添加for word in wordlist:循环的函数,但是有一个起始点和停止点(请参阅下面的代码)。在

from multiprocessing import Pool
import math
import time

cores = 4  # Number of cores to use
wordlist = []

for i in range(127):  # Remove this for your own word list.
    wordlist.append(str(i))  # Creates a large 'word' list for testing.

def pwd_find(start, stop):

    for word in range(start, stop):
        print(wordlist[word])
        time.sleep(0.1)  # Slows things down so it's easier to see that your system is using more than one core.
        ### Add your code here... ###


break_points = []  # List that will have start and stopping points
for i in range(cores):  # Creates start and stopping points based on length of word list
    break_points.append({"start":math.ceil(len(wordlist)/cores * i), "stop":math.ceil(len(wordlist)/cores * (i + 1))})

if __name__ == '__main__':  # Added this because the multiprocessor module acts funny without it.

    p = Pool(cores)  # Number of processors to utilize.
    for i in break_points:  # Cycles though the breakpoints list created above.
        print(i)  # shows the start and stop points.
        a = p.apply_async(pwd_find, kwds=i, args=tuple())  # This will start the separate processes.
    print("Done!")
    p.close()
    p.join()

如果您的代码找到匹配项,请添加p.terminate,然后加p.join来终止处理器。在

如果您想了解更多关于多处理器模块的知识,go here了解更多。在

我希望这能帮助你,或者至少能让你对多处理有一个更好的了解!在

评论 - 2020年7月29日 10:44

最新Python问答

推荐Python问答