Python：打印到文件直到空行？

Question

我目前有：

for i in range (srange, erange):
    lines=open("%s\%s\propkaoutputfiles\propka_protein_output_%s%s.pka" %(filepath, name, aminoacid, i), "r")
    FILE=open("%s\%s\propkamanip\%sinpropka%s.txt" %(filepath, name, aminoacid, i), "w")
    for line in lines:
        if "0.00    0" and " B   7."in line and (line.split()[0]) == "%s" %aminoacid:
            print >> FILE, " %s in %s Structure %s" %(aminoacid, name, i)
            print >> FILE, line
        if "0.00    0" and " B   8."in line and (line.split()[0]) == "%s" %aminoacid:
            print >> FILE, " %s in %s Structure %s" %(aminoacid, name, i)
            print >> FILE, line

我正在读取的数据如下所示，因此我希望在“if-in-line”中嵌入一个代码，该代码将在满足该条件时采用该行，并将文档中的下一行打印到新文件中，直到找到空行：

赖氨酸B 8.X 0.00 0

赖氨酸B

赖氨酸B

这里是空行

参数B 8.9 0.00

这里是Python新手，谢谢！在

Answer 1

file1 = open("your input file", "r")
file2 = open("your output file", "w")

while True :
    line = file1.readline()
    if line :
        if "your criteria ..... " in line :
            file2.write("your header here\n")
            file2.write(line)
            line = file1.readline()
            while line and line != "\n" :
                file2.write(line)
                line = file1.readline()
    else :
        file1.close()
        file2.close()
        break