擅长:python、mysql、java
<p>在序列化程序中尝试此操作:</p>
<pre><code>class ApiLogSerializer(serializers.ModelSerializer):
incoming_data = serializers.JSONField() # change is here
class Meta:
model = ApiLog
fields = ('incoming_data',)
</code></pre>
<p>这将把您的<code>JSON</code>dict转换为字符串,并以<code>Text</code>的形式存储在数据库中。在</p>
<p>有关详细信息,请参阅<a href="http://www.django-rest-framework.org/api-guide/fields/#jsonfield" rel="nofollow noreferrer">official DRF documentation</a></p>