Python等价于Java的“tryLock”（惯用用法）？

Question

在Java中，tryLock(long time, TimeUnit unit)可以用作获取锁的非阻塞尝试。如何在python中实现等效？（最好是Python式的| idiomatic方式！）在

Java tryLock公司：

ReentrantLock lock1 = new ReentrantLock()
if (lock1.tryLock(13, TimeUnit.SECONDS)) { ... }

Python锁：

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Answer 1

可以使用threading模块的Lock.acquire(False)获得“try lock”行为（参见Python doc）：

import threading
import time

my_lock = threading.Lock()
successfully_acquired = my_lock.acquire(False)
if successfully_acquired:
    try:
        print "Successfully locked, do something"
        time.sleep(1)
    finally:
        my_lock.release()
else:
    print "already locked, exit"

我想不出一个令人满意的方法来使用with。在

Answer 2

哎哟，我的错！ 我应该先读一下pythonreference for Locks！在

Lock.acquire([blocking])

When invoked with the blocking argument set to False, do not block. If a call with blocking set to True would block, return False immediately; otherwise, set the lock to locked and return True.

所以我可以做一些类似的事情（或者更高级的事情：p）：

import threading
import time

def my_trylock(lock, timeout):
    count = 0
    success = False
    while count < timeout and not success:
        success = lock.acquire(False)
        if success:
            break
        count = count + 1
        time.sleep(1) # should be a better way to do this
    return success

lock = threading.Lock()
my_trylock(lock, 13)