我正在制作我的第一个python项目,它基本上是一个非常简单的数字猜测终端游戏,目前我正在制作3个关卡中的第一个关卡
这个游戏的工作原理是让python在一定的数字范围内生成一个随机数,然后玩游戏的人必须猜出数字,终端会回答“恭喜你得到了正确的数字”或“哦,你得到了错误的数字”
每当我运行程序时,即使我知道我只有一个数字可供选择,终端也会说我得到的数字不正确,尽管我100%地知道它不是真的。我已经尝试了很多不同的方法。我正在考虑改变数字的格式,比如在一个范围内或类似的东西,但它仍然不承认我的数字是正确的
我的代码不是最好的,但我一直在努力让它变得更好,下面是代码:
import random
import numpy
import time
def get_name():
name = input("Before we start, what is your name?")
print("You said your name was: " + name)
# The Variable 'tries' is the indication of how many tries you have left
tries = 1
while tries < 6:
def try_again(get_number, random, tries):
# This is to ask the player to try again
answer = (input(" Do you want to try again?"))
if answer != "no":
print("Alright!, well I am going to guess that you want to play again")
tries = tries + str(1)
print("You have used up: " + tries + " Of your tries. Remember, when you use 5 tries the game ends")
get_number(get_name, random, try_again)
def find_rand_num(get_number, random, tries):
num_list = [1,1]
number = random.choice(num_list)
# Asks the player for the number
ques = (input("guess your number, since this is the first level you need to choose a number between 1 and 10 "))
print(ques)
if input == number:
print("Congratulations! You got the number correct!")
try_again(get_number, random, tries)
elif input != number:
tries += 1
print("Oops, you got the number wrong")
try_again(get_number, random, tries)
def get_number(get_name, random, try_again, tries, find_rand_num):
# This chooses the number that the player will have to guess
print("The computer is choosing a random number between 1 and 10... beep beep boop")
find_rand_num(get_number, random, tries)
get_name()
get_number(get_name, random, try_again, tries, find_rand_num)
我最近开始学习编程,因为我爸爸也是一名程序员,我希望有一天能和他一样出色。在号码生成问题之后,我还有一些其他错误。我很想听听你对我如何使这部分工作的想法。感谢您抽出时间,祝您今天休息愉快
您正在将input()的结果分配给ques,但是没有使用ques。错误在于“如果输入==数字”。这不是在检查上一次输入调用的结果。它检查函数本身(输入)是否等于一个整数,它永远不会等于
你只是想勾选'number==ques'。然而,这也不太管用。输入返回一个字符串值,您试图将其与整数进行比较。您需要将其转换为int,如“if number==int(ques)”
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