如何在python中从字符串列表中删除多个不需要的字符？

Question

我有以下输入字符串：

text='''Although never is often better than *right* now.

If the implementation is hard to explain, it's a bad idea.

If the implementation is easy to explain, it may be a good idea.

Namespaces are one honking great idea -- let's do more of those!'''

到目前为止，我已经将text字符串拆分为list，如下所示：

^{pr2}$

现在，我想使用strip函数从上面的列表中删除不需要的字符，比如\n\n和{}。在

你能帮我一下吗？？在

Answer 1

使用re模块，^{}函数将允许您这样做。 我们需要用单个的\n替换multilpe\n出现，并删除字符串

import re

code='''Although never is often better than right now.

If the implementation is hard to explain, it's a bad idea.

If the implementation is easy to explain, it may be a good idea.

Namespaces are one honking great idea   let's do more of those!'''


result = re.sub('\n{2,}', '\n', code)
result = re.sub('   ', ' ', result)

print(result)

然后分割你的文本。在

Answer 2

您可以使用列表理解来删除

>>> code='''Although never is often better than right now.
If the implementation is hard to explain, it's a bad idea.
If the implementation is easy to explain, it may be a good idea.
Namespaces are one honking great idea   let's do more of those!'''
>>> 
>>> [word for word in code.split() if word != ' ']
['Although', 'never', 'is', 'often', 'better', 'than', 'right', 'now.', 'If', 'the', 'implementation', 'is', 'hard', 'to', 'explain,', "it's", 'a', 'bad', 'idea.', 'If', 'the', 'implementation', 'is', 'easy', 'to', 'explain,', 'it', 'may', 'be', 'a', 'good', 'idea.', 'Namespaces', 'are', 'one', 'honking', 'great', 'idea', "let's", 'do', 'more', 'of', 'those!']

Answer 3

这将使用空格或换行符拆分字符串

import re

output = [i for i in re.split(r'\s|\n{1:2}| ', code) if i]