数学和变量问题Python3.3

Question

我试图创建一个简单的计算器，但是我使用的IDE一直告诉我我要用字符串执行数学运算。我试着把所有的变量都赋给双精度的，但没用。在

 """Calculator program"""


loop = 1  # 1 means loop; anything else means don't loop.
choice = 0  # This variable holds the user's choice in the menu
add1 = 0.0
add2 = 0.0
sub1 = 0.0
sub2 = 0.0
mul1 = 0.0
mul2 = 0.0
div1 = 0.0
div2 = 0.0
result = 0.0
while loop == 1:
    # Print the options user has
    print ("Welcome to calculator.py")

    print ("your options are:")
    print (" ")
    print ("1) Addition")
    print ("2) Subtraction")

    print ("3) Multiplication")

    print ("4) Division")
    print ("5) Quit calculator.py")
    print (" ")
    #Perform the desired operation
    choice = int(input("Choose your option: ").strip())
    if choice == 1:
        add1 = input()
        add2 = input()
        result = add1 + add2
        print(add1, add2)
        print (add1, "+", add2, "=", result)
    elif choice == 2:
        sub2 = input()
        sub1 = input()
        result = sub1 - sub2
        print (sub1, "-", sub2, "=", result)
    elif choice == 3:
        mul1 = input("Multiply this: ")
        mul2 = input("with this: ")
        result = mul1 * mul2
        print (mul1, "*", mul2, "=", result)
    elif choice == 4:
        div1 = input("Divide this: ")
        div2 = input("by this: ")
        result = div1 / div2
        print (div1, "/", div2, "=", result)
    elif choice == 5:
        loop = 0

print ("Thank-you for using calculator.py!")

Answer 1

input()返回字符串，而不是数字。你必须把它转换成：

add1 = int(input())

或者

^{pr2}$

取决于你希望你的计算器支持什么，否则你实际上是在用字符串执行数学运算。在

Answer 2

试着粘上

    int()

在它上面制造

^{pr2}$

希望这有帮助