擅长:python、mysql、java
<p>另一种方法是:</p>
<pre><code>def get_feedback(mark, out_of):
percentage = int((mark / out_of) * 100)
if percentage >= 80:
return "Excellent"
elif 60 <= percentage <= 79:
return "Good"
elif 50 <= percentage <= 59:
return "Pass"
else:
return "Not a pass"
</code></pre>