强制DecimalField将字符串转换为十进制Django

Question

我有一个序列化程序：

class Ticker24hSerializer(serializers.Serializer):
        change = serializers.DecimalField(max_digits=19, decimal_places=4)
        change_percent = serializers.FloatField()
        current = serializers.DecimalField(max_digits=19, decimal_places=4)
        high = serializers.DecimalField(max_digits=19, decimal_places=4)
        low = serializers.DecimalField(max_digits=19, decimal_places=4)
    
        def update(self, instance, validated_data):
            pass
    
        def create(self, validated_data):
            pass

字典包含如下的十进制值：

dict = {
    "change": "2128.5000",
    "change_percent": "5.632",
    "current": "39517.3141",
    "high": "40900.0000",
    "low": "37350.0000"
}

但是，这些值作为字符串存储在字典中

当我序列化dict时：

result = serializer(dict).data
print(result)

我明白了：

{
    "change": "2128.5000",
    "change_percent": 5.632,
    "current": "39517.3141",
    "high": "40900.0000",
    "low": "37350.0000"
}

小数字段接受字符串，如何使序列化程序存储小数