将日期与过去的一天进行比较

Question

x=['2020-05-12 20:16', '2020-05-12 20:16', '2020-05-10 20:11', '2020-05-10 20:07', '2020-05-11 20:03', '2020-05-8 20:02', '2020-05-8 20:02', '2020-05-9 20:02',]
@staticmethod    
def compare_time(post_time):
            date_object = datetime.strptime(post_time, "%Y-%m-%d %H:%M")
            past = datetime.now() - date_object

如何编辑我的函数，使其返回True如果日期不早于昨天（在当前时间的24小时内），否则返回False，我觉得我已经完成了一半，但不确定下一步该做什么

Answer 1

您需要量化2个datetime对象之间的差异，^{}这里是

A timedelta object represents a duration, the difference between two dates or times.

您希望我们的持续时间低于24h/1d，因此需要< timedelta(days=1)或< timedelta(hours=24)

def compare_time(post_time):
    date_object = datetime.strptime(post_time, "%Y-%m-%d %H:%M")
    past = datetime.now() - date_object
    return past < timedelta(days=1) # from datetime import timedelta

Answer 2

根据1天的timedelta测试差异datetime.now() - date_object：

from datetime import datetime, timedelta

x = ['2020-05-12 20:16', '2020-05-12 20:16', '2020-05-10 20:11', 
     '2020-05-10 20:07', '2020-05-11 20:03', '2020-05-8 20:02', 
     '2020-05-8 20:02', '2020-05-9 20:02',]

def compare_time(post_time):
    date_object = datetime.strptime(post_time, "%Y-%m-%d %H:%M")
    return (datetime.now() - date_object) < timedelta(days=1)

for t in x:
    print(t, compare_time(t))
# 2020-05-12 20:16 True
# 2020-05-12 20:16 True
# 2020-05-10 20:11 False
# 2020-05-10 20:07 False
# 2020-05-11 20:03 False
# 2020-05-8 20:02 False
# 2020-05-8 20:02 False
# 2020-05-9 20:02 False