所以我为我的类编写了一个基本的登录系统,我使用for循环和计数器来线性搜索列表。但是,当我输入一个应该正确的用户名时,它返回为未经授权。我试着在每次循环之间打印计数器,我发现即使范围是(0,6),它最多只能计数三次
image of code, shell and error message
import random
userver = 0
userList = ["Arabella12", "Constance01", "Hugo11", "James09", "Jane12", "Max06", "Ted04"]
pwrdList = ["bella12", "1234", "HGWel!", "j@me£S", "Password", "notpassword", "ted4"]
found = False
pfound = False
def login():
username = input("Type in your username ")
index1 = 0
wrong = 0
found = False
c3 = 0
print("index one before c3 loop=", index1) #delete after testing
for c3 in range(0, 6): #username check counter
if username == userList[c3]: #if username is found with the counter c3
found = True #making the key for the next part of the code true
index = s(c3)
print(index," is the index")
c3 = c3 + 1
break
elif found == False:
print("c3: ", c3) #checking counter- delete after debugging
print("unauthorised user...attempting again") #if username isnt present
c3 = c3 + 1 #upping the counter
exit
login()
范围不正确,因为您使用了
“
而不是"
。此外,您不需要在elif中使用exit并增加计数器-这是自动完成的相关问题 更多 >
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