擅长:python、mysql、java
<p>试试下面的方法</p>
<pre><code>dict_Xero_Profile ={'a': ['Demo'],
'b': ['PMS'],
'c' : ['All'],}
x = ['Demo','PMS']
res = {k: l for k, l in dict_Xero_Profile.items() if ''.join(l) in x}
print(res)
</code></pre>
<p>输出</p>
<pre><code>{'a': ['Demo'], 'b': ['PMS']}
</code></pre>