列表字典和元组列表比较

Question

所以我试图让我的列表字典与我的元组列表相匹配。（希望这是有道理的）。我有一本以列表为值的字典，我的值是每本书的单独分数，例如：bob上的值5等于图书列表中的第一本书：

d = {'bob':[5,0,0,1,3], 'toms':[3,0,5,3,0], 'sammy': [0,0,0,1,0], 'ted':[5,0,0,6,3]}

和元组列表：

books=[('Douglas Adams', "The Hitchhiker"), ('Richard Adams', 'Watership'), ('Mitch Albom', 'The Five People'), ('Laurie Anderson', 'Speak'), ('Maya Angelou', 'Caged Bird Sings')]

所以我想要的是能够说，当某人的值为3或6时，我可以把他们拉出来，告诉他们什么书有这样的评级。 谢谢

编辑： 我希望它能输出某种类型的字典，它会说：

selectScores = {bob: ('Maya Angelou', 'Caged Bird Sings'), toms: (Maya Angelou', 'Caged Bird Sings', Laurie Anderson', 'Speak')} 

对每个人来说都是如此

像这样的东西，我希望是输出

Answer 1

你可以试试这样的。基本上枚举字典值并使用其索引访问books数组

d = {'bob':[5,0,0,1,3], 'toms':[3,0,5,3,0], 'sammy': [0,0,0,1,0], 'ted':[5,0,0,6,3]}
books=[('Douglas Adams', "The Hitchhiker"), ('Richard Adams', 'Watership'), ('Mitch Albom', 'The Five People'), ('Laurie Anderson', 'Speak'), ('Maya Angelou', 'Caged Bird Sings')]

select_scores = {}
for key, books_scores in d.items():
    for i, score in enumerate(books_scores):
        if score == 3 or score == 6:
            if key not in select_scores:
                select_scores[key] = []
            select_scores[key].append(books[i])
            
print(select_scores)

输出：

{'bob': [('Maya Angelou', 'Caged Bird Sings')], 'toms': [('Douglas Adams', 'The Hitchhiker'), ('Laurie Anderson', 'Speak')], 'ted': [('Laurie Anderson', 'Speak'), ('Maya Angelou', 'Caged Bird Sings')]}