返回包含给定时间（当前时间）的时隙

Question

我有一张六小时的时段表。我需要构建一个函数，如果当前时间在以下情况下，该函数将返回其中一个时隙：

From 00:00 - to 05:59 -> # should return -> 00:00
From 06:00 - to 11:59 -> # should return -> 06:00
From 12:00 - to 17:59 -> # should return -> 12:00
From 18:00 - to 23:59 -> # should return -> 18:00

I asked for a similar function that returns the closest and furthest time to the current time at: https://stackoverflow.com/a/68240328/14712981. I used the same code from @RJ Adriaansen for my current question but it didn't work as expected.

代码如下：

current_time = '10:00'
time = ['00:00','06:00','12:00','18:00']

def get_time(time):
  return datetime.strptime(time, '%H:%M')


current_time = get_time(current_time)
time = [get_time(i) for i in time]

print(min(time,key=lambda x : abs(current_time-x)).strftime('%H:%M'))

# It returns 12:00, while it should return 06:00 in my case.

有人能告诉我解决这个问题需要做什么吗

Answer 1

abs(current_time)忽略x是在current_time之前还是之后，因此它返回最近的时隙，而不是从current_time之前开始的最近的时隙

如果时间段已排序，只需循环，直到找到一个小于或等于当前时间的时间段

for slot in time:
    if slot <= current_time:
        print(slot.strftime('%H:%M'))
        break

如果它们尚未排序，请使用for slot in sorted(time):