擅长:python、mysql、java
<p>如果我没弄错,你需要做的就是迭代<br/><code>zip(daycoords1, daycoords1[1:])</code>并进行计算。演示:</p>
<pre><code>>>> daycoords1 = [(1,2), (3,4), (5,6)]
>>> for x in zip(daycoords1, daycoords1[1:]):
... print(x)
...
((1, 2), (3, 4))
((3, 4), (5, 6))
</code></pre>
<p>如果有很多坐标,请考虑<code>itertools.izip</code>以提高内存效率。在</p>