在CSV中编写词典列表

Question

下一个问题是，您有一个该格式的词典列表

[{'a': 10, 'b': 11, 'c': 12, 'd': 13, 'e': 14}, 
 {'a': 20, 'b': 21, 'c': 22, 'd': 23, 'e': 24}, 
 {'a': 30, 'b': 31, 'c': 32, 'd': 33, 'e': 34}, 
 {'a': 40, 'b': 41, 'c': 42, 'd': 43, 'e': 44}]

您要将其移动到CSV文件，如下所示

"a","b","c","d","e"  
 10,11,12,13,14
 20,21,22,23,24
 30,31,32,33,34
 40,41,42,43,44

问题是，当您启动代码时：

def write_csv_from_list_dict(filename, table, fieldnames, separator, quote):
    table = []
    for dit in table:
        a_row = []
        for fieldname in fieldnames:
            a_row.append(dit[fieldname])
        table.append(a_row)
    file_handle = open(filename, 'wt', newline='')
    csv_write = csv.writer(file_handle,
                           delimiter=separator,
                           quotechar=quote,
                           quoting=csv.QUOTE_NONNUMERIC)
    csv_write.writerow(fieldnames)
    for row in table:
        csv_write.writerow(row)
    file_handler.close()

上升误差

(Exception: AttributeError) "'list' object has no attribute 'keys'" 
at line 148, in _dict_to_list wrong_fields = rowdict.keys() - self.fieldnames

为什么这么难说，明确地关闭一个文件，而不是一个字符串

Answer 1

下面的代码应该可以工作

data = [{'a': 10, 'b': 11, 'c': 12, 'd': 13, 'e': 14},
        {'a': 20, 'b': 21, 'c': 22, 'd': 23, 'e': 24},
        {'a': 30, 'b': 31, 'c': 32, 'd': 33, 'e': 34},
        {'a': 40, 'b': 41, 'c': 42, 'd': 43, 'e': 44}]
keys = data[0].keys()
with open('data.csv', 'w') as f:
    f.write(','.join(keys) + '\n')
    for entry in data:
        f.write(','.join([str(v) for v in entry.values()]) + '\n')

data.csv

a,b,c,d,e
10,11,12,13,14
20,21,22,23,24
30,31,32,33,34
40,41,42,43,44