Python3将可变数量的列表合并为一个列表

Question

下面的代码会导致（行）列表数量可变：

BoM = sock.execute(dbname,uid,pwd,'mrp.bom.line','search',[('bom_id','=',Pname)])
for BoMs in BoM:
    RAWnames = sock.execute(dbname,uid,pwd,'mrp.bom.line','read',BoMs)
    RAWnames = RAWnames[0]
    LdM = RAWnames['product_id'][1], RAWnames['product_qty'], RAWnames['x_studio_custo_unitrio']
    BoM = list(LdM)
    print (BoM)

像这个：

['Material 1', 1.0, 1.0]
['Material 2', 2.0, 2.0]
['Material 3', 3.0, 3.0]
['Material 2', 2.0, 2.0]
['Material 3', 3.0, 3.0]
['Material 4', 4.0, 4.0]

我需要将这些列表合并为一个列表，因此结果如下：

[['Material 1', 1.0, 1.0],
['Material 2', 2.0, 2.0],
['Material 3', 3.0, 3.0],
['Material 2', 2.0, 2.0],
['Material 3', 3.0, 3.0],
['Material 4', 4.0, 4.0]]

我怎样才能做到这一点？这可能吗？ 不知何故，我一直认为这应该很容易，但我不能全神贯注

Answer 1

您可以定义一个列表并将每条记录附加到其中

records = []

BoM = sock.execute(dbname,uid,pwd,'mrp.bom.line','search',[('bom_id','=',Pname)])
for BoMs in BoM:
    RAWnames = sock.execute(dbname,uid,pwd,'mrp.bom.line','read',BoMs)
    RAWnames = RAWnames[0]
    LdM = RAWnames['product_id'][1], RAWnames['product_qty'], RAWnames['x_studio_custo_unitrio']
    BoM = list(LdM)

    records.append(BoM)

print(records)

Answer 2

list1 = ['Material 1', 1.0, 1.0]
list2 = ['Material 2', 2.0, 2.0]
list3 = ['Material 3', 3.0, 3.0]
list4 = ['Material 2', 2.0, 2.0]
list5 = ['Material 3', 3.0, 3.0]
list6 = ['Material 4', 4.0, 4.0]

mergedList = []

mergedList.append(list1)
mergedList.append(list2)
mergedList.append(list3)
mergedList.append(list4)
mergedList.append(list5)
mergedList.append(list6)

print(mergedList)

Answer 3

试试这个：

mergedList = [list1, list2, list2, list3, list4, list5, list6]