如何检查日期是否在一定范围内？

Question

我正在写一个程序来帮助管理我的梦幻足球联赛。作为其中的一部分，我需要确定我们将在哪一周比赛。对于那些不熟悉的人来说，梦幻足球周并不符合标准周，每个梦幻周从周二开始，到下一个周一结束

我是Python的新手，我已经编写了一些代码来完成我想做的事情，但是我相信有更好的方法来完成。我很好奇，将来有什么更好的办法来解决这个问题。特别是，我不想每个赛季都改变这些变量

import datetime

timenow = datetime.datetime.now().date()
week1start = datetime.date(day=9, month=9, year=2021)
week1end = datetime.date(day=13, month=9, year=2021)
week2start = datetime.date(day=14, month=9, year=2021)
week2end = datetime.date(day=20, month=9, year=2021)
week3start = datetime.date(day=21, month=9, year=2021)
week3end = datetime.date(day=27, month=9, year=2021)
week4start = datetime.date(day=28, month=9, year=2021)
week4end = datetime.date(day=4, month=10, year=2021)
week5start = datetime.date(day=5, month=10, year=2021)
week5end = datetime.date(day=11, month=10, year=2021)
week6start = datetime.date(day=12, month=10, year=2021)
week6end = datetime.date(day=18, month=10, year=2021)
week7start = datetime.date(day=19, month=10, year=2021)
week7end = datetime.date(day=25, month=10, year=2021)
week8start = datetime.date(day=26, month=10, year=2021)
week8end = datetime.date(day=1, month=11, year=2021)
week9start = datetime.date(day=2, month=11, year=2021)
week9end = datetime.date(day=8, month=11, year=2021)
week10start = datetime.date(day=9, month=11, year=2021)
week10end = datetime.date(day=15, month=11, year=2021)
week11start = datetime.date(day=16, month=11, year=2021)
week11end = datetime.date(day=22, month=11, year=2021)
week12start = datetime.date(day=23, month=11, year=2021)
week12end = datetime.date(day=29, month=11, year=2021)
week13start = datetime.date(day=30, month=11, year=2021)
week13end = datetime.date(day=6, month=12, year=2021)
week14start = datetime.date(day=7, month=12, year=2021)
week14end = datetime.date(day=13, month=12, year=2021)
week15start = datetime.date(day=14, month=12, year=2021)
week15end = datetime.date(day=20, month=12, year=2021)
week16start = datetime.date(day=21, month=12, year=2021)
week16end = datetime.date(day=27, month=12, year=2021)


def get_current_week():
    if timenow < week1start:
        return 0
    elif week1start <= timenow <= week1end:
        return 1
    elif week2start <= timenow <= week2end:
        return 2
    elif week3start <= timenow <= week3end:
        return 3
    elif week4start <= timenow <= week4end:
        return 4
    elif week5start <= timenow <= week5end:
        return 5
    elif week6start <= timenow <= week6end:
        return 6
    elif week7start <= timenow <= week7end:
        return 7
    elif week8start <= timenow <= week8end:
        return 8
    elif week9start <= timenow <= week9end:
        return 9
    elif week10start <= timenow <= week10end:
        return 10
    elif week11start <= timenow <= week11end:
        return 11
    elif week12start <= timenow <= week12end:
        return 12
    elif week13start <= timenow <= week13end:
        return 13
    elif week14start <= timenow <= week14end:
        return 14
    elif week15start <= timenow <= week15end:
        return 15
    elif week16start <= timenow <= week16end:
        return 16

Answer 1

使用楼层划分的简单解决方案：

start = datetime.date(day=7, month=9, year=2021)
timenow = datetime.date.today()
week = (timenow - start).days // 7 + 1