边界之间的多重匹配

Question

我试图在一个字符串中进行多重匹配，但我只需要找到一些边界之间的匹配

假设我在字符串中有以下字符串和标志。我只需要找到介于HELLO和BYE标志之间的“123.12”

Lorem Ipsum是*123.12*印刷和*123.12*行业的虚拟文本*123.12*Ipsum是16世纪业界的*123.12*虚拟文本，当时一个未知的*123.12*取了*123.12*的一个厨房，并将其置乱为*123.12*一个样本*123.12*。您好，*123.12*不仅经历了*123.12*个世纪，*123.12*还跨越了*123.12*排版，保持了*123.12*不变。再见，在*123.12*1960年代，随着包含Lorem Ipsum段落的Letraset表单的发布，它是*123.12*，最近，随着桌面出版软件*123.12*Aldus PageMaker*123.12*版本*123.12*Ipsum的发布

现在我正在对所有具有我需要的特征的子字符串进行匹配，但它在我需要的范围之外进行匹配

PS：引擎是python，不能添加任何库

Answer 1

string = """Lorem Ipsum is *123.12* dummy text of the printing and *123.12* industry. *123.12* Ipsum has been the industry's *123.12* dummy text ever *123.12* the 1500s, when an unknown *123.12* took a galley of *123.12* and scrambled it to *123.12* a type specimen *123.12*. HELLO *123.12* has survived not only *123.12* centuries, *123.12* also the leap into *123.12* typesetting, remaining *123.12* unchanged. BYE It was *123.12* in *123.12* 1960s with the release of Letraset sheets containing Lorem Ipsum passages, and more recently with desktop publishing software *123.12* Aldus PageMaker *123.12* versions of *123.12* Ipsum."""

startFlag = 'HELLO'
endFlag = 'BYE'

lookingFor = '*123.12*'

EndOfStartFlagIndex = string.index(startFlag) + len(startFlag)

betweenFlags = string.split(startFlag)[1].split(endFlag)[0]

lookingForInices = [i+EndOfStartFlagIndex for i in range(0,len(betweenFlags)) if betweenFlags[i:i+len(lookingFor)] == lookingFor]

print(lookingForInices)