无法从数据帧(Python)获取序列

2024-05-20 22:29:18 发布

您现在位置:Python中文网/ 问答频道 /正文

a = np.random.standard_normal((9,4))
dg = pd.DataFrame(a)
dg.columns = [["No1", "No2", "No3", "No4"]]
dg["No1"]

大家好。我一直在使用通过Anaconda Navigator打开的JupyterLab,并编写了上述代码。前三行看起来正常,但是,对于第四行,我得到了一个错误,如下所示。如果我把第四行改成dg[[“No1”]],那么它“起作用了”。然而,在这种情况下,类型(dg[[“No1”]])实际上是数据帧,而不是序列

我有点糊涂,我已经搔了将近两个小时的头,仍然不明白出了什么问题。有人能帮忙吗?谢谢


TypeError                                 Traceback (most recent call last)
<ipython-input-393-b26f43cf53bf> in <module>
----> 1 dg["No1"]

~\anaconda3\lib\site-packages\pandas\core\frame.py in __getitem__(self, key)
   2774                 if self.columns.nlevels > 1:
   2775                     return self._getitem_multilevel(key)
-> 2776                 return self._get_item_cache(key)
   2777 
   2778         # Do we have a slicer (on rows)?

~\anaconda3\lib\site-packages\pandas\core\generic.py in _get_item_cache(self, item)
   3584         res = cache.get(item)
   3585         if res is None:
-> 3586             values = self._data.get(item)
   3587             res = self._box_item_values(item, values)
   3588             cache[item] = res

~\anaconda3\lib\site-packages\pandas\core\internals\managers.py in get(self, item)
    966                         raise ValueError("cannot label index with a null key")
    967 
--> 968             return self.iget(loc)
    969         else:
    970 

~\anaconda3\lib\site-packages\pandas\core\internals\managers.py in iget(self, i)
    983         Otherwise return as a ndarray
    984         """
--> 985         block = self.blocks[self._blknos[i]]
    986         values = block.iget(self._blklocs[i])
    987 

TypeError: only integer scalar arrays can be converted to a scalar index

Tags: keyinpycoreselfpandasgetreturn