我正在使用python制作一个discord聊天机器人,我的机器人使用API发送新闻,但我无法做到这一点
我的代码:-
import requests
def get_news(): #========================================News
url = "https://google-news1.p.rapidapi.com/top-headlines"
load_dotenv()
querystring = {"country":"INDIA","lang":"en","limit":"50","media":"true"}
headers = {
'x-rapidapi-key': "os.getenv('NEWS_API')",
'x-rapidapi-host': "google-news1.p.rapidapi.com"
}
response = requests.request("GET", url, headers=headers, params=querystring)
json_data=json.loads(response.text)
return json_data
@client.event
async def on_message(message):
if message.content.startswith('|news'): #====================================News
data=get_news()
list1=message.content.split(" ")
try:
num=int(list1[1])
except:
num=5
i = 1
for item in data['article']:
if not(item['description']):
continue
await message.channel.send(str(i)+". "+item['url'])
if i == num:
break
i += 1
我正在使用来自https://rapidapi.com/ubillarnet/api/google-news1/的API
但我面临一些错误
我的错误:-
$ python -u "d:\Code\python projects\Discord_Chat_BOT\main.py"
We have logged in as Buddy#9784
Ignoring exception in on_message
Traceback (most recent call last):
File "C:\Users\soham\AppData\Roaming\Python\Python39\site-packages\discord\client.py", line 343, in _run_event
await coro(*args, **kwargs)
File "d:\Code\python projects\Discord_Chat_BOT\main.py", line 218, in on_message
for item in data['article']:
KeyError: 'article'
请帮助我修复此错误
我认为原因是:
您实际上是将文本
"os.getenv('NEWS_API')"
作为键发送,而不是运行os.getenv('NEWS_API')
并将值作为键发送。由于字符串"os.getenv('NEWS_API')"
不是有效的密钥,因此您没有权限相反,请删除引号以发送实际密钥:
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