将标准输入转换为数据帧

2024-06-16 13:15:00 发布

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我有标准输入:

'Town3, NYC, Town1, Town4, Town5, Town6, Town2
 67, 69, 60, 63, 65, 69, 95'

我想知道如何将其转换为熊猫数据帧,以便获得:

   Town3  NYC  Town1  Town4  Town5  Town6  Town2
0     67   69     60     63     65     69     95

Tags: 数据标准nyctown3town1town2town6town4
2条回答

您可以使用io.StringIO+pd.read_csv

import pandas as pd
from io import StringIO

s = """Town3, NYC, Town1, Town4, Town5, Town6, Town2
 67, 69, 60, 63, 65, 69, 95"""

df = pd.read_csv(
    StringIO(s),
    sep=r",\s*",
    engine="python",
)

print(df)

印刷品:

   Town3  NYC  Town1  Town4  Town5  Town6  Town2
0     67   69     60     63     65     69     95

将字符串拆分为列表。把它切成两等份。第一部分是列,第二部分是值:

s = 'Town3, NYC, Town1, Town4, Town5, Town6, Town2, 67, 69, 60, 63, 65, 69, 95'
l = s.split(', ')

df = pd.DataFrame([l[len(l)//2:]], columns=l[:len(l)//2])
>>> df

  Town3 NYC Town1 Town4 Town5 Town6 Town2
0    67  69    60    63    65    69    95

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