Python中十六进制颜色的字符串格式

2024-03-27 22:19:44 发布

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我从PHP修改了一个函数来返回颜色渐变(http://www.herethere.net/~samson/php/color_gradient/color_gradient_generator.php.txt). 返回以0结尾的彩色十六进制代码时遇到问题。此函数为:

def _get_color(current_step=0, start='000000', end='ffffff', max_steps=16):
    '''
        Returns the color code for current_step between start and end
    '''
    start = '{0:#x}'.format(int(start, 16))
    end = '{0:#x}'.format(int(end, 16))

    if int(max_steps) > 0 & int(max_steps) < 256:
        max_steps = max_steps
    else:
       max_steps = 16

    r0 = (int(start, 16) & 0xff0000) >> 16
    g0 = (int(start, 16) & 0x00ff00) >> 8
    b0 = (int(start, 16) & 0x0000ff) >> 0

    r1 = (int(end, 16) & 0xff0000) >> 16
    g1 = (int(end, 16) & 0x00ff00) >> 8
    b1 = (int(end, 16) & 0x0000ff) >> 0

    if r0 < r1:
        r = int(((r1-r0)*(float(current_step)/float(max_steps)))+r0)
    else:
        r = int(((r0-r1)*(1-(float(current_step)/float(max_steps))))+r1)

    if g0 < g1:
        g = int(((g1-g0)*(float(current_step)/float(max_steps)))+g0)
    else:
        g = int(((g0-g1)*(1-(float(current_step)/float(max_steps))))+g1)

    if b0 < b1:
        b = int(((b1-b0)*(float(current_step)/float(max_steps)))+b0)
    else:
        b = int(((b0-b1)*(1-(float(current_step)/float(max_steps))))+b1)

    return '{0:#x}'.format(((((r << 8) | g) << 8) | b))

当我以黑色的#000000运行循环时,我只返回0。第二个代码f0f0f也缺少0。在

^{pr2}$

注意前两个十六进制代码。对如何正确格式化返回值返回000000有什么想法?在


Tags: stepcurrentfloatb0stepsstartmaxb1