如何从n个列表中形成所有可能的组合

Question

这个问题很难在标题中表达出来，因此需要一个例子：

我有3个清单：

L1 = ["Eagle", "Panther"]

L2 = ["Warrior", "Talon", "Machete"]

L3 = ["Feather", "Raptor", "Hunter", "Piranha"]

列表可以有不同的大小

我想形成所有子集{[a,b,c]}，这样a在L1，b在L2，c在L3

例如：

{["Eagle", "Warrior", "Feather"], ["Eagle", "Warrior", "Raptor"], ["Panther", "Machete", "Feather"]...}

["Eagle", "Warrior", "Feather"]与["Eagle", "Feather", "Warrior"]相同，因此顺序并不重要

我只需要所有的子集

我看到许多帖子，我可以在其中形成一个列表的子集，但在这里找不到我要找的内容。我显然可以循环并执行它，但我想知道是否有itertools解决方案

Answer 1

import itertools
L1=["Eagle","Panter"]
L2=["Warrior","Talon","Machete"]
L3=["Feather","Raptor","Hunter","Piranha"]
res=set()
for i in itertools.product(L1,L2,L3):
    res.add(tuple(sorted(i)))
print(res)

Answer 2

itertools.product用于此

import itertools

L1 = ["Eagle", "Panther"]

L2 = ["Warrior", "Talon", "Machete"]

L3 = ["Feather", "Raptor", "Hunter", "Piranha"]

for x in itertools.product(L1,L2,L3):
    print(x)

输出

('Eagle', 'Warrior', 'Feather')
('Eagle', 'Warrior', 'Raptor')
('Eagle', 'Warrior', 'Hunter')
('Eagle', 'Warrior', 'Piranha')
('Eagle', 'Talon', 'Feather')
('Eagle', 'Talon', 'Raptor')
('Eagle', 'Talon', 'Hunter')
('Eagle', 'Talon', 'Piranha')
('Eagle', 'Machete', 'Feather')
('Eagle', 'Machete', 'Raptor')
('Eagle', 'Machete', 'Hunter')
('Eagle', 'Machete', 'Piranha')
('Panther', 'Warrior', 'Feather')
('Panther', 'Warrior', 'Raptor')
('Panther', 'Warrior', 'Hunter')
('Panther', 'Warrior', 'Piranha')
('Panther', 'Talon', 'Feather')
('Panther', 'Talon', 'Raptor')
('Panther', 'Talon', 'Hunter')
('Panther', 'Talon', 'Piranha')
('Panther', 'Machete', 'Feather')
('Panther', 'Machete', 'Raptor')
('Panther', 'Machete', 'Hunter')
('Panther', 'Machete', 'Piranha')