如何打印文件中的所有电话号码

Question

此代码仅打印第一个电话号码。如何打印文件中的所有电话号码

import re


def findn(filename):
    phonenum= re.compile(r'05\d\d\d\d\d\d\d\d')
    with open(filename) as f:
        for line in f:
            phone_number = re.search(phonenum, line)
            if phone_number:

                print("phone number found: "+phone_number.group())
            else:
                print('none')
        print('done')


findn("1.txt")

Answer 1

要逐行打印文件，只需使用2行for循环即可

file = open("name_of_file.txt", "r")

for line in file:
    print(line)

然后，您可以将该行保存到变量中，以便稍后在循环中使用-

file = open("name_of_file.txt", "r")

for line in file:
    phonenb = line

或者，您可以使每一行成为列表中的一个元素-

file = "name_of_file.txt"
lines = [line.split() for line in open(file)]
print(lines)

Answer 2

用re.findall()替换re.search()可能会起作用（由于我没有1.txt文件，所以无法测试）。这是因为re.search()只查找匹配的实例，而re.findall()查找所有实例

import re

def findn(filename):
    phonenum= re.compile(r'05\d\d\d\d\d\d\d\d')
    with open(filename) as f:
        for line in f:
            phone_number = re.findall(phonenum, line)
            if phone_number:
                print("phone number found: "+phone_number.group())
            else:
                print('none')
        print('done')


findn("1.txt")