您将如何压缩此代码？python

Question

我正在制作一个地牢游戏，但它是一个8x8瓷砖网格，但我需要用木瓷砖填充所有的地牢。你知道我怎么做吗？我试着先放置8块瓷砖，然后再向下放置8块瓷砖

import pygame
pygame.init()
screen = pygame.display.set_mode([510, 510])
wood_floor = pygame.image.load('Desktop/Python Game 1/wood_floor.png')

x = 0
y = 0
for i in range(8):
    screen.blit(wood_floor, (x, y))
    x += 64
x = 0
for i in range(8):
    screen.blit(wood_floor, (x, 64))
    x += 64
x = 0
for i in range(8):
    screen.blit(wood_floor, (x, 128))
    x += 64
x = 0
for i in range(8):
    screen.blit(wood_floor, (x, 192))
    x += 64
x = 0
for i in range(8):
    screen.blit(wood_floor, (x, 256))
    x += 64
x = 0
for i in range(8):
    screen.blit(wood_floor, (x, 320))
    x += 64
x = 0
for i in range(8):
    screen.blit(wood_floor, (x, 384))
    x += 64
x = 0
for i in range(8):
    screen.blit(wood_floor, (x, 448))
    x += 64

Answer 1

使用//（楼层分割）运算符和%（模）运算符：

for i in range(64):
    screen.blit(wood_floor, ((i // 8) * 64, (i % 8) * 64))

---

要提高性能，请在表面上创建一个大的pygame.Surface对象和blit瓷砖：

board = pygame.Surface((8*64, 8*64))
for i in range(64):
    board.blit(wood_floor, ((i // 8) * 64, (i % 8) * 64))

blit应用程序循环中的board表面连续：

while run:
    # [...]

    screen.blit(board, (0, 0))

Answer 2

这段代码工作得最好：

x = 0
y = 0
for i in range(64):
    screen.blit(wood_floor, (x, y))
    x += 64
    if x == 512:
        y += 64
        x = 0

Answer 3

基于Rabbi76的答案，但使用坐标作为循环变量，以避免循环体中的额外乘法：

for y in range(0, 8 * 64, 64):
    for x in range(0, 8 * 64, 64):
        screen.blit(wood_floor, x, y)