擅长:python、mysql、java
<p>假设您希望字符串作为输出,则只需要2个嵌套循环,运行在<code>i</code>和<code>j</code>到<code>size</code>之间:</p>
<pre><code>>>> [[list2[j] + list1[(i+j)%size] for j in range(size)] for i in range(size)]
[['xa', 'yb', 'zc'], ['xb', 'yc', 'za'], ['xc', 'ya', 'zb']]
</code></pre>