我有密码:
def get_address_query(trader_id, connection):
cursor = connection.cursor()
sql_address_data = "SELECT * FROM address where id = '%s' AND type = 'registered'"
cursor.execute(sql_address_data, trader_id)
address_query = cursor.fetchall()
if address_query is None:
raise Exception("address details do not exist")
else:
return address_query
我编写了以下测试:
@mock.patch('lambda_function.pymysql')
def test_get_address_query(self, mock_database_connection):
mock_record = (('test',),('first',),('last',))
mock_database_connection.cursor.return_value.fetchall.return_value = mock_record
result = lambda_function.get_address_query('test', 'connection')
self.assertEqual(result, mock_record)
但我犯了以下错误:
id = 'test', connection = 'connection'
def get_address_query(id, connection):
> cursor = connection.cursor()
E AttributeError: 'str' object has no attribute 'cursor'
../lambda_function.py:92: AttributeError
我知道错误是由于我没有正确模拟connection.cursor.fetchall造成的,但我不确定如何正确操作。任何帮助都将不胜感激
您将字符串
'connection'
作为第二个参数传递给了get_address_query()
然后在
get_address_query()
内,它使用第二个参数connection
(一个字符串)调用方法.cursor()
这就像调用
'connection'.cursor()
显然会失败,因为str没有这样的方法相反,您需要做的是将模拟对象
mock_database_connection
传递给connection
参数。这样,所有对connection
的调用(如connection.cursor()
)都将使用配置的模拟对象以下是您可能希望用作参考的最低测试代码:
输出:
cursor.fetchall()
的响应与我们在模拟对象mock_database_connection
中配置的一样李>相关问题 更多 >
编程相关推荐